Activity Answers
Broadcast 2


Weekly Weather Log
Each week please complete the following information for both our location here off the coast of Australia and the location at your school. Each week students should complete the weekly log with the weather information at their school. Mrs. Linsley will send the ship weather report by email following each broadcast. Students can record this information at that time. Also, the front page of the web site will always display the time and date in Australia.

  My School Ship in Australia

Temperature

*
27°C

Day and Time

*
January 24, 2001 @ 10:00am
Precipitation
[indicate snow, sleet or rain]
*
None
Skies or Cloud Bank
*
No Report
Season
*
High Summer
Wind Speed and Direction
*
18-22 Knots S.E.


Formula for Converting Celsius to Fahrenheit:
F= (1.8 X C) +32
C=F-32/1.8

1 Knot = 1 nautical mile per hour (1 nautical mile = 6076 feet or 1852 meters)

Cloud Cover is recorded by a code which lists the coverage in eights:
Code:Eights
0:0
1:1/8 or less
2:2/8
3:3/8
4:4/8
5:5/8
6:6/8
7:7/8
8:8/8 Overcast
9: obscured or cloud amount cannot be determined

Questions/Activities
[Complete the questions below prior to the broadcasts, if at all possible]

This week's question is:
Calculate the weight of drill pipe string.

To keep the arithmetic simple you can use 20 lbs / foot (or 60 lbs / meter) for the weight of the drill pipe. The length of pipe used will vary from site to site depending on the water depth and the depth drilled into the sea floor. The water depth at most of the sites to be drilled on Leg 194 is in the range 900-1500 feet, and the depth to be drilled into the sea floor in each case will be 1350-1800 feet.

For the purpose of this problem:
Given, the weight of the drill pipe stated above, the water depth equal to 1200 feet and the depth drilled into the sea floor of 1800 feet, calculate the weight of the drill pipe string
[Note remember to include the units].

The total weight of the pipe string is simply the length (in feet or meters) multiplied by the weight per foot, and the total length of the pipe is the water depth plus the depth the pipe extends into the sea floor:
(Water depth + Depth below seafloor)
X Weight per unit length = Total weight
Thus, if the water depth is 1200 feet and the pipe extends 1800 feet into the sea floor, and the weight of the pipe per foot is 20 lbs:
Total weight = (1200 ft + 1800 ft) X 20 lbs/ft = 3000 X 20 lbs = 60, 000 lbs

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